Question

Two resistors of resistance 3 ohm and 6 ohm respectively are connected to a battery of 6 volt so find maximum current

Answer 1

if it is connected in series then maximum current would be 0.67A.If it is connected in parallel then maximum current would be 3A

Answer 2

Answer:

The maximum current will be 3 A.

Explanation:

Given that,

Resistance $R_{1}=3\ ohm$

Resistance $R_{2}=6\ ohm$

Voltage $V=6\ volt$

If two resistors are connected in a series.

Then, The equivalent resistance will be

$R = R_{1}+R_{2}$

$R = 3+6$

$R=9\ ohm$

Using Ohm's law

The voltage is the product of the current and resistance.

$V= IR$

$I =\dfrac{V}{R}$

$I=\dfrac{6}{9}$

$I=0.67\ A$

If two resistors are connected in a parallel

Then, The equivalent resistance will be

$\dfrac{1}{R} =\dfrac{1}{R_{1}}+\dfrac{1}{R_{2}}$

$\dfrac{1}{R} =\dfrac{1}{3}+\dfrac{1}{6}$

$\dfrac{1}{R} =\dfrac{1}{2}$

$R=2\ ohm$

Using Ohm's law

$I =\dfrac{6}{2}$

$I=3\ A$

Therefore, The current will be maximum when the resistance are connected in parallel.

Hence, The maximum current will be 3 A.