Question

Two resistors of resistance 5 ohm each is connected in parallel. The effective resistance of this combination will be

Answer 1

Answer:

Explanation:

The formula for effective resistance in a parallel combination is

1/R=1/R1+1/R12

therefore 1/R=1/5+1/5

1/R=2/5

R=5/2

R=2.5

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Answer 2

Explanation:

We know, effective resistance is

$\frac{1}{r } = \frac{1}{r1} + \frac{1}{r2}$

So,

$\frac{1}{r} = \frac{1}{5} + \frac{1}{5}$

$= ) \frac{1}{r } = \frac{2}{5}$

$= )r = \frac{5}{2} ohm$