Two resistors of resistance 6Ω and 12Ω are connected in a) series and b) parallel combination, across a potential of 10V. Calculate the current flowing through the circuit in each case.
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Answered by
1
R
eff
=6+
12+6
12×6
=10Ω
I=1A
∴V
AB
=10−6×1=4V
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Plz mark brainliast
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