two resistors of resistance R1 and R2 having R1 greater than R2 are connected in parallel for equivalent resistance R the correct statement is
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Answer:
Explanation:
In parallel combination of resistance the equivalent resistance is less than the lowest resistance .
So ,in this case R will be smaller than both R1 and R2 but R2 is even smaller than R1 .
Therefore the answer will be
R<R2<R1
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Your question was incomplete. Please check below the full content.
Options:
A. R> R1+R2
B. R1<R<R2
C. R2<R< (R1+R2)
D. R<R1
Concept:
- The parallel arrangement of resistors
- Equivalent resistance
Given:
- R1>R2
- Resistors are connected in parallel
Find:
- The relation between equivalent resistance R, R1 and R2
Solution:
For the parallel arrangement of resistors,
1/R = 1/R1 +1/R2
1/R = (R1+R2)/R1R2
R = R1R2/(R1+R2)
Equivalent resistance R is less than any of the resistors arranged.
The correct option is R<R1
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