Question

Two resistors of resistances 1 ohm and 2 ohm are connected in series in the circuit to a 3
V battery. What would be the reading of ammeter and the voltmeter connected to 2 ohm
resistor when the circuit is closed?​

Answer 1

Answer :-

→ Reading of the ammeter is 1 Ampere .

→ Reading of the voltmeter is 2 Volt .

Explanation :-

We have :-

• 2 Resistances are connected in series .

• Resistances are 1 Ω and 2 Ω .

• Voltage of the battery = 3 V

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Equivalent resistance will be :-

R = R₁ + R₂

⇒ R = 1 + 2

⇒ R = 3 Ω

Now, let's calculate the total current flowing through the circuit using Ohm's Law :-

V = IR

⇒ 3 = I × 3

⇒ I = 3/3

⇒ I = 1 A

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It is given that the ammeter and voltmeter are connected to the '2 Ω' resistor .

As the resistances are connected in series so the same current will flow through the both resistances. Thus, the ammeter will show a reading of 1 A .

Now, let's calculate the reading of the voltmeter using Ohm's Law :-

⇒ V₂ = IR₂

⇒ V₂ = 1 × 2

⇒ V₂ = 2 V

Answer 2

Given :-

Two resistors of resistances 1 ohm and 2 ohm are connected in series in the circuit to a 3  V battery.

To Find :-

What would be the reading of ammeter and the voltmeter connected to 2 ohm  resistor when the circuit is closed?​

Solution :-

Since they are connected in series

So,

Equivalent resistance = R1 + R2

Equivalent resistance = 1 + 2

Equivalent resistance = 2 ohm

Now

In Ammemeter

I = V/R

I = 3/3

I = 1 Ampere

In Voltmeter

They are connected witha 2 ohm resistor. So, resistance is 2 ohm

Now

V = IR

V = 1 × 2

V = 2 Volt

Diagram