Two resistors of resistances 10 oh and 20 ohm are connected in parallel. A battery supplies 6A of current to the combination, calculate the current in each resistor
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equalent resistance = (10×20)/30 =20/3 ohm
I = 6A
so V=IR = 20/3 × 6= 40volt
now current at 10ohm resister is I=V/R
I=40/10 = 4 A
I = 20/10= 2A
I = 6A
so V=IR = 20/3 × 6= 40volt
now current at 10ohm resister is I=V/R
I=40/10 = 4 A
I = 20/10= 2A
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