two resistors of resistances 10 ohm and 20 ohm are joined in series. a potential difference of 12 volt is applied across the combination. find the power consumed by each resistor
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Given that 2 resistors of 10 ohm and 20 ohm are connected in series.
Total resistance (R) = R₁+R₂ = 10+20 = 30Ω
Potential difference (V) = 12v
Power consumed (P) = ?
From ohms law, V = iR
i = V/R ----- 1
We know that, P = iV
From 1, P = V²/R
Placing the given values in the formula
P = 12 x 12 / 30
P = 4.8 w
Therefore, Power consumed = 4.8 watts
Total resistance (R) = R₁+R₂ = 10+20 = 30Ω
Potential difference (V) = 12v
Power consumed (P) = ?
From ohms law, V = iR
i = V/R ----- 1
We know that, P = iV
From 1, P = V²/R
Placing the given values in the formula
P = 12 x 12 / 30
P = 4.8 w
Therefore, Power consumed = 4.8 watts
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