Two resistors of resistances 10ohm and 20 ohm are joined in parallel. A potential difference of 12V is applied across the combination. Find the power consumed by each resistor
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2
Voltage in parellel arrangement is constant
Power consumed by each resistor are
P₁ = V²/R₁
= (12 Volt)² / 10 Ω
= 14.4 Watt
P₂ = V²/R₂
= (12 Volt)² / 20 Ω
= 7.2 Watt
Power consumed by each resistor are
P₁ = V²/R₁
= (12 Volt)² / 10 Ω
= 14.4 Watt
P₂ = V²/R₂
= (12 Volt)² / 20 Ω
= 7.2 Watt
Answered by
0
Answer:
4.8 watts
Explanation:
Given that 2 resistors of 10 ohm and 20 ohm are connected in series.
Total resistance (R) = R₁+R₂ = 10+20 = 30Ω
Potential difference (V) = 12v
Power consumed (P) = ?
From ohms law, V = iR
i = V/R ----- 1
We know that, P = iV
From 1,
P = V²/R
Placing the given values in the formula P = 12 x 12 / 30
. P = 4.8 w
Therefore, Power consumed = 4.8 watts .
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