Two resistors of resistances 3Ω and 6Ω are connected in parallel across a
battery having a voltage of 12 V. Determine a) the total circuit resistance b)
the current flowing in the 3Ω resistor
Answers
Answered by
34
a) total Resistance : 1/3 + 1/6 ohm
1/2 ohm
0.5 ohm
b) R = 3 ohm
V = 12 v
As, V = I × R
I = V / R
I = 12/3
So, I = 4
Current = 4 A
1/2 ohm
0.5 ohm
b) R = 3 ohm
V = 12 v
As, V = I × R
I = V / R
I = 12/3
So, I = 4
Current = 4 A
Answered by
6
Explanation:
total resistance =2 ohms
current flowing through 3 ohm resistor= 4 A
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