Question

Two resistors of resistances 3 and 6  respectively are connected to a battery of 6 V so as to have (a) minimum resistance, (b) minimum current. (i) How will you connect the resistances in each case? Calculate the strength of the current in the circuit in both cases.

Answer 1

Answer:

(a) (i) For minimum current we must make R maximum. This can be done by connecting the resistances in series.

(ii) For maximum current we must make R minimum. This can be done by connecting the resistances in parallel.

(b) (i)R

eq

=R

1

+R

2

=5+10=15Ω

I=

R

eq

V

=

15

6

=0.4A

(ii) R

eq

=

R

1

+R

2

R

1

R

2

=

5+10

5×10

=3.33Ω

I=

R

eq

V

=

3.33

6

=1.8A