Question

Two resistors of resistances 4 and 12 Q
are connected (i) in parallel and (it) in series.
Calculate the values of effective resistance in
each case​

Answer 1

Answer:

Explanation:hope it helped u

Answer 2

Solution :-

Given that the value of Resistances

» 4Ω and 12Ω

Now first we will connect them in parallel circuit.

» Parallel circuit :- The circuit in which the potential difference across the Resistances are same.

Now equivalent Resistance in Parallel circuit :-

$R_{eq} = \left(\dfrac{1}{r_1} + \dfrac{1}{r_2} + \dfrac{1}{r_3} .... + \dfrac{1}{r_n}\right)^{-1}$

So equivalent Resistance

$= \left(\dfrac{1}{4} + \dfrac{1}{12}\right)^{-1} \\\\ = \left(\dfrac{3 + 1}{12}\right)^{-1} \\\\ = \left(\dfrac{4}{12}\right)^{-1} \\\\ = \left(\dfrac{1}{3}\right)^{-1} \\\\ = 3\Omega$

Now we will connect them in series

» Series circuit :- A circuit in which the current across the Resistances are same.

Equivalent Resistance in a Series

$R_{eq} = r_1 + r_2 + r_3 ..... + r_n$

Now equivalent Resistance

$= 4 + 12$

$= 16 \Omega$