Two resistors of resistances 6 Ω and 12 Ω, are connected first in series, and then in parallel in a circuit
across a battery of 6 V. Calculate the ratio of the heat produced in the series combination to that of
the parallel combination of resistors.
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Answer:
In series R = 6+12 =18
In parallel 1/R =1/6 +1/12 =1/4 so R =4
Heat produced will be proportional to v^2/R
So,it is (1/18^2) : (1/4^2) = 4 : 81
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