Question

two resistors of values 35 ohms and 14 ohms are connected in parallel with 7v battery . find equivalent resistance, current through each resistor and net current... pls help me with correct explanation. thank u​

Answer 1

AnswEr :

Given that ,

The two resistor 35 ohm and 14 ohm are connected in parrallel combination with 7 v battery

We know that , the equivalent resistance in parrallel combination is given by

$\large \rm \fbox{ \frac{1}{R } = \frac{1}{R_{1}} + \frac{1}{R_{2}} + ... + \frac{1}{R_{n}} }$

Thus ,

$\sf \mapsto \frac{1}{R} = \frac{1}{35} + \frac{1}{14} \\ \\ \sf \mapsto \frac{1}{R} = \frac{14 + 35}{490} \\ \\ \sf \mapsto R = \frac{490}{49} \\ \\ \sf \mapsto R =10 \: \: ohm$

$\therefore \sf \underline{The \: equivalent \: resistance \: is \: 10 \: ohm}$

We know that ,

$\large \rm \star \: \: \fbox{V = IR} \: \: \{ \because \: Ohm's \: law\}$

Thus , the current in each resistor will be

7 = I × 35

I = 0.2 amp

And

7 = I × 14

I = 0.5 amp

$\therefore \sf \underline{The \: current \: in \: each \: resistor \: are \: 0.2 \: amp \: and \: 0.5 \: amp}$

Now , the net current will be

7 = I × 10

I = 0.7 amp

$\therefore \sf \underline{The \: net \: current \: is \: 0.7 \: amp }$

Answer 2

Answer:

GIVEN:

Length of rectangle = 10m

Breadth of rectangle = 5m

Side of square = 8 m

TO FIND:

Compare the area of rectangle and square

SOLUTION:

We know that the formula for finding the area of rectangle is:-

$\large{\boxed{\bf{\star \: AREA = Length \times Breadth \: \star}}}$

To find the area of the square, we use the formula:-

$\large{\boxed{\bf{\star \: AREA = (Side)^2 \: \star}}}$

According to question:-

$\large\bf{\star \: Length \times Breadth = (Side)^2 \: \star}$

On putting the given values in the formula, we get

$\rm{\hookrightarrow 10 \times 5 = (8)^2 }$

$\rm{\hookrightarrow 50 = 64 }$

Divide by '2' on both sides

$\bf{\hookrightarrow 25 = 32 }$

❝ Hence the comparison between the area of rectangle and square is 25 and 32 respectively. ❞

______________________GIVEN:

Length of rectangle = 10m

Breadth of rectangle = 5m

Side of square = 8 m

TO FIND:

Compare the area of rectangle and square

SOLUTION:

We know that the formula for finding the area of rectangle is:-

$\large{\boxed{\bf{\star \: AREA = Length \times Breadth \: \star}}}$

To find the area of the square, we use the formula:-

$\large{\boxed{\bf{\star \: AREA = (Side)^2 \: \star}}}$

According to question:-

$\large\bf{\star \: Length \times Breadth = (Side)^2 \: \star}$

On putting the given values in the formula, we get

$\rm{\hookrightarrow 10 \times 5 = (8)^2 }$

$\rm{\hookrightarrow 50 = 64 }$

Divide by '2' on both sides

$\bf{\hookrightarrow 25 = 32 }$

❝ Hence the comparison between the area of rectangle and square is 25 and 32 respectively. ❞

______________________

GIVEN:

Length of rectangle = 10m

Breadth of rectangle = 5m

Side of square = 8 m

TO FIND:

Compare the area of rectangle and square

SOLUTION:

We know that the formula for finding the area of rectangle is:-

$\large{\boxed{\bf{\star \: AREA = Length \times Breadth \: \star}}}$

To find the area of the square, we use the formula:-

$\large{\boxed{\bf{\star \: AREA = (Side)^2 \: \star}}}$

According to question:-

$\large\bf{\star \: Length \times Breadth = (Side)^2 \: \star}$

On putting the given values in the formula, we get

$\rm{\hookrightarrow 10 \times 5 = (8)^2 }$

$\rm{\hookrightarrow 50 = 64 }$

Divide by '2' on both sides

$\bf{\hookrightarrow 25 = 32 }$

❝ Hence the comparison between the area of rectangle and square is 25 and 32 respectively. ❞

______________________