Two resistors, R_1=48\ \OmegaR 1
=48 ΩR, start subscript, 1, end subscript, equals, 48, space, \Omega and R_2=12\ \OmegaR 2
=12 ΩR, start subscript, 2, end subscript, equals, 12, space, \Omega, are connected in parallel across a cell of voltage, V_{\text{cell}}=24\ \text VV cell
=24 VV, start subscript, start text, c, e, l, l, end text, end subscript, equals, 24, space, start text, V, end text, as shown below.
Answers
Given : Two resistors R₁ = 48 Ω and R₂ = 12 Ω connected in parallel across 24V battery
To Find : Total current , Total resistance , current through each resistor
Solution:
R₁ = 48 Ω
R₂ = 12 Ω
Reff = R
1/R = 1/48 + 1/12
=> 1/R = ( 1 + 4)/48
=> 1/R = 5/48
=> R = 48/5
=> R = 9.6 Ω
I = V/R
Total Current = 24 /9.6 = 2.5 A
Current through R₁ 48 Ω = 24/48 = 0.5 A
Current through R₂ 12 Ω = 24/12 = 2 A
9.6 Ω is effective resistance
Total current = 2.5A
Current through R₁ 48 Ω = 0.5 A
Current through R₂ 12 Ω = 2 A
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