Question

two resistors r and 12 ohm are connected in parallel in circuit if the resultant resistors in circuit is 4 ohms then find the value of R​

Answer 1

Answer:

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Answer 2

Answer:

Two resistors R and 12 ohms are connected in parallel in a circuit if the resultant of these resistors in this circuit is 4 ohms then the value of R​ is

6Ω

Explanation:

• A resistor is  used to resist the current flow through  a circuit

• If two resistors with resistances $R_{1} ,R_{2}$ are connected in parallel in a circuit the effective resistance that appeared in the circuit is given by the formula

             $1/R_{eff} =1/R_{1} +1/R_{2}$

          ⇒$R_{eff} =\frac{R_{1} R_{2} }{R_{1} +R_{2} }$

from the question, we have given that

one of the resistances $R_{1} =12$ Ω

the effective resistance of the circuit $R_{eff} =4$ Ω

substitute the given values to get the other resistance

⇒$4=\frac{12R_{2} }{12+R_{2} }$

⇒$4*12+4R_{2} =12R_{2}$

⇒

$48=8R_{2}\\R_{2}=48/8=6$ Ω