Question

Two resistors R1= 60ohms and R2=240ohms are connected in series, to that series connection resistor Rl=600ohms is connected in parallel. Supply voltage is 230 volts. Caculate current in suppl line

Answer 1

Answer

1.15 Amperes

Step-by-step explanation:

R1 = 60ohm

R2= 240ohm

R3=600ohm

V= 230V

R1 and R2 are in series combination, while R3 is in parallel to this series

Let total resistance across R1 and R2 be Rx

Rx = 60+ 240

Rx= 300ohm

Total resistance in the circuit be R

1÷R = (1÷Rx) +(1÷R3)

1÷R=(1÷300) +(1÷600)

1÷R = (3÷600)

1÷R = (1÷200)

R = 200ohm

By Ohm's law,

I(current)= V(Potential difference)÷R(Resistance)

i= 230÷200

i=1.15 Amperes

Therefore, the current across is 1.15 Amperes