Physics, asked by unknowngamer70063959, 20 days ago

Two resistors R1 and R2 are connected in series in a circuit having the resultant resistance of 6 Ohms. If the value of resistance for the resistor R2 is 2 Ohms, calculate the value of resistance for the resistar R1

Answers

Answered by meetdchaudhari2006
8

Answer:

R1 + R2 = R

R1 + 2 = 6

R1 = 6 - 2

R1 = 4 Omhs

please mark me as the brainliest

Answered by hiabhibadan1234
20

Given: Resultant resistance(R)=6ohms

           R2=2ohms

To find: The value of resistance for the resistor R1

Solution:

Resistance of a circuit is defined as the obstruction to the flow of current and it can be connected in a circuit in two ways:

  1. Series
  2. Parallel

As the resistors, R1 and R2 are connected in series,

∴R= R1+R2

⇒R1=R-R2

⇒R1=6-2  [∵R=6 ohms and R2=2 ohms]

⇒R1=4 ohms

Hence, the value of resistance for the resistor R1 is 4 ohms.

Similar questions