Question

. Two resistors R1 and R2 are connected in series with a battery of 6V. If R1 = 1 ohm and R2 = 2 ohm, then what is the current passing through the circuit?

Answer 1

Answer:

I(current) = 2A

Explanation:

R1 = 1 ohm ; R2 = 2 ohm ; Potential difference= 6V

as R1 & R2 are connected in series ,

Equivalent resistance = 1 + 2 = 3 ohm

so current = 6/3 = 2A