Question

Two resistors R1 and R2 of 4 12 and 6 12 are connected in parallel across a
battery. The ratio of power dissipated in them, P1: P2 will be
(A)4:9
(B)3:2
(C)9:4
(D)2:3​

Answer 1

Answer:

Explanation:

In parallel combination potential differences(V) remains same

so power dissipated in resistance(R)=[(V)^2]/R

here potential is same so

P1=[(V)^2]/4

P2=[(V)^2]/6

P1:P2=3:2

hence option B