Two resistors R1 and R2 of 4Ω and 6Ω are connected in parallel across a battery . The ratio of power dissipated in them P1:P2=?
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p=V2/R
As the resis tors are connected in parallel to battery ,both have same potential
so,
px 1/r
p1/p2= r2/r
6/4=3/2
=3:2
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