Two resistors R1 and R2 with resistance 5 ohm and 10 ohm respectively are connected in series. The voltage across R1 is 4V. What will be the value of current across R2?
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Given: The resistance of the first resistor(R1)= 5ohm
The resistance of the second resistor(R2)= 10ohm
The voltage across the first resistor(V1) = 4V
To find The value of current across R2
Solution: In an electric circuit, when there is a hindrance to the current's flow, this is known as resistance.
From the question, the resistors R1 and R2 are in series, and we know for a circuit that is connected in series, the current flowing through that circuit is constant or the same. So we can tell that the current flowing through the first resistor with resistance R1 and having a voltage V1 is exactly the same as the current flowing through the second resistor.
∴ The current across the first resistor(I1)= V1/R1
=4/5 A
= 0.8 A
So, therefore 0.8A current is also flowing through the second resistor as the circuit is in series.
Hence the value of the current across R2 is 0.8A