Question

Two resistors RA=20Ω and RB=60Ω are connected in parallel and draws a current of 10A

from a source. Determine the current through the 60Ω resistor​

Answer 1

Answer:

The current through 60Ω resistor is 2.5 ampere.

Step-by-step explanation:

$\huge \color{blue}\boxed{ \color{purple}\boxed{ \color{yellow}\boxed{ \mathfrak{ \colorbox{red}{Given :-}}}}}$

$:\implies \: R_A=20Ω$

$:\implies \: R_B=60Ω$

$:\implies \: current = 10A$

$\color{brown} \mathbb{We \: know \: that,}$

$\frac{1}{R} = \frac{1}{R_1} + \frac{1}{ R_2}$

$\frac{1}{R} = \frac{1}{20} + \frac{1}{60}$

$\frac{1}{R} = \frac{3 + 1}{60}$

$\frac{1}{R} = \frac{4}{60}$

$R = \frac{60}{4}$

$\boxed{R = 15 \: Ω} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: (1)$

$\color{red} \mathbb{We \: Know \: That,}$

$\mathbb{V=IR}$

$\implies \: V=10 \times 15 \: \: \: \: \: (from \: 1)$

$\mathbb{\implies \: \boxed{V=150}} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: (2)$

$\color{green} \mathbb{Now \: for \: 60Ω \: resistor,}$

$\mathbb{Using \: Ohm's \: law}$

$\mathbb{V=IR}$

$150 = \mathbb{I \times 60} \: \: \: \: \: \: \: \: \: \: \: \: \: (from \: 2)$

$\mathbb{I} = \frac{150}{60}$

$\boxed{\mathbb{I} = 2.5 \: ampere}$

Hence, the current through 60Ω resistor is 2.5 ampere.