Physics, asked by kausthub8599, 2 months ago

Two resistors when connected in series the net resistor is 7 ohm when the same two resistor are connected in parallel the net resistor is 12 by 7 l .find the value of resistor

Answers

Answered by dokejaya8
0

Answer:

Given that 2Ω and 4Ω are connected in parallel,

So,

2

1

+

4

1

=

R

eq1

1

R

eq1

1

=

8

6

=

4

3

3

4

=1.3333Ω

Again 3Ω and 6Ω are coonected in parallel,

So,

3

1

+

6

1

=

R

eq2

1

R

eq2

1

=

18

9

18

9

=2Ω

Now, R

eq1

and R

eq2

are coonected in series,

So, R

eq

=R

eq1

+R

eq2

+InternalResistance

⇒R

eq

=1.333+2+0.7

⇒R

eq

=4.0333Ω

So,

I=

R

V

=

4.033

5

=1.239Amp≃1.24Amp

I

4

=

R

3

+R

2

R

3

⋅I

⇒I=

3+6

3×1.24

=

9

3.72

=0.4133Amp

So, The current through 6Ω is 0.4133Amp

Explanation:

hope it's helpfulark me as brainleast

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