Two resistors when connected in series, their effective resistance is 9 ohm. Their effective resistance become 2ohm when they are connected in parallel. Find the value of the resistors.
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Answer:
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Explanation:
resistors assumed R1 AND R2
series resistance 9 -----A
Parallel Resistance 2----B
in series resistance R1+R2=9
IN parallel resistance R1×R2/(R1+R2) = 2
THEREFORE R1×R2=18
SO R1=18/R2 -------C
C in A
R²2 + 18= 9R2
R²2 -6R2 -3R2 +18=0 (FACTORISING)
R2 (R2- 6) -3(R2 -6)=0
So
R2=6 THEREFORE R1=3
OR
R1=3 THEREFORE R2=6
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