Question

two resistors which have resistance 2 ohm 3ohm in such way resultant resistance is minimum then find the resultant resistance​

Answer 1

Answer:

Given: R 1=2ohm, R 2 =3 ohm, R 3 =6

ohmFormula: 1/R= 1/R1+ 1 / R2+ 1 /R3= 1/2 + 1/3 + 1/6

∴R= 3+2+1/6= 6/6 =1ohm.

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Answer 2

Given :

We are given two resistors of 2Ω and 3Ω.

To Find :

We are asked to connect these resistors in such way resultant resistance is minimum$.$

Solution :

❖ In order to get minimum equivalent resistance we have to connect them in parallel.

Equivalent resistance of the parallel connection is given by

• 1/R = 1/R₁ + 1/R₂ + ... + 1/Rₙ

By substituting the given values;

➙ 1/R = 1/R₁ + 1/R₂

➙ 1/R = 1/2 + 1/3

➙ 1/R = (3 + 2) / 6

➙ R = 6/5

➙ R = 1.2 Ω

Knowledge BoosteR :

• In series combination, current through each resistor is same but potential difference across the resistors may be different.
• In parallel connection, potential difference on each resistor is same but the current through resistors may be different.
• In order to get maximum equivalent resistance, we need to connect all resistors in series.