Question

two resistors with resistance 10 ohm and 15 ohm are connected to a battery of 12V .Calculate the strength of rlectric current in each circuit

Answer 1

Answer:

Circuit 1(when resistance is 10 ohm)

current will be 1.2A

Circuit 2(when resistance is 15 ohm)

Current will be 0.8A

Explanation:

We know that, V=IR.

so, I=V/R

Answer 2

Answer :

1.2A and 0.8A

Explanation:

According to ohm's law

At constant Temperature "the current flowing in a circuit is directly proportional to the applied voltage and inversely proportional to the resistance offered between them".

By using ohm's law

I=V/R

let R1=10ohm and R2=15ohm

V=12V (the voltages are same) then

I1=V/R1=12/10=1.2 Amps

I2=V/R2= 12/15=0.8 Amps

the unit of electric current is Ampers and it is denoted by 'A'

the current flowing through a circuit are 1.2A and 0.8A respectively