Two resistors with resistance 10ohm and 15ohm are connected to a 12volt battery so as to obtain and measurethe maximum current
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Hey there !!!!
From Ohm's law Voltage = Current*Resistance
V=IR
I=V/R
At constant voltage Current is inversely proportional to resistance.
So we need less resistance to produce more current.
Series combination of two resistors gives maximum resistance and minimum current.
Parallel Combination of 2 resistors gives minimum resistance and maximum current.
So ,R₁=10 Ω and R₂= 15Ω must be in parallel connection
Equivalent resistance of parallel connection 1/R= 1/R₁ + 1/R₂
1/R= 1/10+1/15
1/ R=(3+2)/30
1/R=5/30=1/6
R=6Ω V=12V
Current I = V/R =12/6 =2 A
Hope this helped you ...................
From Ohm's law Voltage = Current*Resistance
V=IR
I=V/R
At constant voltage Current is inversely proportional to resistance.
So we need less resistance to produce more current.
Series combination of two resistors gives maximum resistance and minimum current.
Parallel Combination of 2 resistors gives minimum resistance and maximum current.
So ,R₁=10 Ω and R₂= 15Ω must be in parallel connection
Equivalent resistance of parallel connection 1/R= 1/R₁ + 1/R₂
1/R= 1/10+1/15
1/ R=(3+2)/30
1/R=5/30=1/6
R=6Ω V=12V
Current I = V/R =12/6 =2 A
Hope this helped you ...................
abhi178:
Nice
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