Two resistors with resistance 5ohm & 10ohm are connected to a battery of 6V.Calculate the strength of the total current in the circuit in two cases:
a)maximum
b)minimum
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a )1/ R = 1/5+1/10=3/10. HENCE R=10/3 ohm . V= 6V
so, I = V/R = 6/10/3=6×3/10=18/10=1.8A
b) R= 5+10=15ohm . V = 6V .
Hence, I= V/R= 6/15=0.4A
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