Question

Two resistors with resistances 10 ohm and 15 ohm are to be connected to a battery of emf 12 V so as to obtain :1) minimum current.2) maximum current.   A) How will you connect the resistance in each case .   B) Calculate the strength of total current in the circuit in the 2 cases.

Answer 1

1)
For minimum current, Resistance has to be maximum. So they must be connected in series. Total Resistance = 10+15 = 25 ohm
Current, I = 12/25 = 0.48 Amp

2)
For maximum current, Resistance has to be minimum. So they must be connected in parallel. Total Resistance = $\frac{10\times15}{10+15}$ = 6 ohm
Current, I = 12/6 = 2.0 Amp

Answer 2

Answer:

Explanation:

From the ohms law

I=V/R

I=12/10

I=1.2Amp

Provided:

No other element or no other source connected in the circuit.

If any other source or element connected use Kvl and calculate the voltage across the resistor 10 ohm. Then calculate current flowing in resistor by applying I=V/R.