Two resistors with resistances 5 ohm and 10 ohm are to be connected to a battery of emf 6 V so as to obtain :1) minimum current.2) maximum current. A) How will you connect the resistance in each case . B) Calculate the strength of total current in the circuit in the 2 cases.
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1 minimum current = 6/15 = 0.4 amp ( resistance in series)
2 maximum current = 6×3/10 = 1.8 amp(resistance in parallel)
2 maximum current = 6×3/10 = 1.8 amp(resistance in parallel)
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