Question

Two resistors3Ωand 6Ω are connected first in series and then in parallel. The

ratio of the effective resistors will be 1 mark

a) 2:9 b) 1:3 c) 9:2 d) 1:2​

Answer 1

The answer is option c

In series,

R= R1 + R2

R= 3+6

R= 9ohm

In parallel,

1/R = 1/R1 + 1/R2

1/R = 1/3 +1/6

1/R = 2+1/6

1/R = 3/6

R= 6/3

R= 2 ohm

So the ratio of effective resistor is 9:2 (series : parallel)