Question

Two right angled triangle abc and dbc are on the same hypotenuse

Answer 1

Hey buddy here is ur answer !!!!

Given:

Two right triangles ABC and BBC on the same hypotenuse BC- AC

and BD intersect at P.

To prove: APx PC=BPx PD

Proof: In △ABP and △DCP

∠A - ∠D (- 90°) (given)

∠APB = ∠DPC (vertically opposite angles)

∴△ABP ~ △DCP (AA similarity axiom)

∴ AB = BP = AP

(corresponding sides of similar △ s are proportional).....(1)

DC = CP = DP

From (1)

BP/CP = AP/DP

By cross multiplication,

BP x DP = AP x PC (proved).

hope u like my process....

plz mark it as brainalist....

Answer 2

Answer:

hope this answer useful to you mate