Question

Two right circular cones A and B are made. A having
3 times the radius of B, and B having half the volume
of a A.calculate the ratio of heights of A & B.

Answer 1

ANSWER

The cone x has radius = 3r

The cone y has radius = r

Volume of x = 2v

Volume of y = v

∴2v=

3

1

π(3r)

2

×h...(i)

and

v=

3

1

πr

2

h

y

...(ii)

Divide (i) by (ii)

2=

hy

9hx

⇒

hy

hx

=

9

2

plz mark me brainliest

Answer 2

$\huge\star\underbrace {\mathtt\red {A}\mathtt\red {n} \mathtt\red {s}\mathtt\red {w}\mathtt\red {e}\mathtt\red {r}} \star\:$

• A cone is a 3d figure ....( see the attachment)

$\huge{\mathbb{\purple{ G{\pink{I{\green{V[\blue{E{\red{ N{\orange{:}}}}}}}}}}}}]$

Ratio of A is 3 timed ratio of B

$\huge{\mathbb{\purple{ A{\pink{N{\green{S[\blue{W{\red{ E{\orange{R}}}}}}}}}}}}]$

Ratio is

$\frac{2}{9}$

$\huge{\mathbb{\purple{ S{\pink{O{\green{L[\blue{U{\red{ TI{\orange{ON}}}}}}}}}}}}]$

$va \times \frac{1}{2} = vb$

☆Volume of cone =

$\frac{1}{3} \times \pi {r}^{2} h$

$\frac{1}{ 3}\pi {r}^{2} h = \frac{1}{3} \times \pi {r}^{2} h$

• I/3 and pi cancels out
• Substituting value of r

$9 {r}^{2} h1 = {r}^{2} h2$

• r² cancels out

$so \: \: \frac{h1}{h2} = \frac{2}{9}$

.................(Answer ) ✌

$<marquee behaviour-move> <font color="</strong><strong>fushsia</strong><strong>"> <h1>#ANSWER</strong><strong>=</strong><strong>2</strong><strong>/</strong><strong>9</strong><strong></ ht> </marquee>$

____________

Hope it helps

Mark as BRAINLIEST

$\huge\purple{\mathfrak{@phenom}}$