two right circular cylinders of equal volumes have their Heights in the ratio 1:2 what is the ratio of their radii
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Let two cylinders be of the form as attached
Then According to Question,
π(R')²2H = πR²H
(R'/R)² = πH/π2H
(R'/R)² = 1/2
R'/R = 1/√2
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☺☺☺ Hope this Helps ☺☺☺
Then According to Question,
π(R')²2H = πR²H
(R'/R)² = πH/π2H
(R'/R)² = 1/2
R'/R = 1/√2
_________________________________________________________
☺☺☺ Hope this Helps ☺☺☺
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