Question

Two rings of the same radius and mass m are placed such that the

Answer 1

Complete your question plzz!!

Answer 2

The moment of Inertia of such a system would be (3/2)MR2 .

The moment of Inertia of the system = The moment of Inertia of Ring rotating about an axis perpendicular to its plane + The moment of Inertia of Ring rotating about an axis in its own plane.

The moment of Inertia of Ring rotating about an axis perpendicular to its plane= MR2

The moment of Inertia of Ring rotating about an axis in its own plane.= MR2/2

So the moment of inertia of the system is(3/2)MR2



Hope this helps....♥♥♥