Math, asked by vedprakash51211, 4 months ago

Two road of width 3m run perpendicular to each other in the middle of garden as shown in figure the garden is of length 100m and breadth 80m the road are laid at cost of ₹11 Per metre square and the remaining garden is levelled at ₹5 per m square find the total amount spent

Answers

Answered by shreekrishna35pdv8u8
4

Step-by-step explanation:

L = 100m

B = 80m

wide of road = 3m

area of rectangle = l*b = 100*80 =800m²

area of road =

100 \times 3  + 80  \times 3 - 3 \times 3 \\  = 300 + 240 - 9 \\  = 531 {m}^{2}

cost per for road construction = 11

cost of 531m² for road construction = 531*11 =

5841

area of remaining garden = 800 - 531 =269m²

cost per levelling = 5

cost of 269m² levelling = 269*5 = 1345

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