Math, asked by sunilkumar629912, 1 month ago

Two roads 3m wide have been constructed in the middle of a garden crossing each other at right angles, running parallel to the sides of the garden 35m long and 25 m wide. find the cost of the constructing the roads at the at the rate of 80 per m sq. ​

Answers

Answered by HAZZARD
0

Step-by-step explanation:

width =5 m

length of first parallel road 70 m

area of first road 70×5=350 sq.m

length of second road 45 m 

area of second road =45×5=225 sq.m

area of the common part of cross road with 5 m width that  lies at the 

center of the park 5×5 = 225 sq.m 

area of roads = area of first road +area of second cross road−common area

                                           =(350+225)−25=575−25=550sqm

cost of the construction per sq.m =Rs.105

total cost =550×105=Rs 57750

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