Two roads of width 3 m run perpendicular to each other in the middle of a garden. The garden is of length 100 m and breadth 80 m. The roads are laid at a cost of Rs.11 per m² and the remaining garden is leveled at Rs.5 per m². Find the total amount spent
Answers
Here, we will consider the cost of leveling the roads and the garden separately.
Now, the area of both the roads together = 2 × 100 m × 3 m
= 600 m²
Also, area of the whole garden = length × breadth
= 100 m × 80 m
= 8000 m²
Now, are of remaining garden (without roads) = 8000 m² - 600 m²
= 7400 m²
Thus, cost of leveling roads = 600 m² × Rs. 11
= Rs. 6600
Also, cost of leveling remaining garden = 7400 m² × Rs. 5
= Rs. 37000
Thus, total amount spent = Rs. 6600 + Rs. 37000
= Rs. 43600
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