Question

Two rods A and B of same length and radius are joined together. the thermal conductivity of A and B are 2 K and K. under steady state conditions If temperature difference between the open ends of A and B is 36 °c, the temperature difference across A is

Answer 1

Explanation:

Given Two rods A and B of same length and radius are joined together. the thermal conductivity of A and B are 2 K and K. under steady state conditions If temperature difference between the open ends of A and B is 36 °c, the temperature difference across A is

• Let theta be the temperature of interface of rods A and B. At the steady state
• Given K1 = 2K and K2 = K
• We need to find temperature difference across A.
• We get  (ΔQ / Δt)A = (ΔQ / Δt) B
• K1 A (36 – theta ) / x = K2 A(theta – 0) / x
• 2KA(36 – theta) / x = KAtheta / x
• 36 – theta = theta / 2
• 72 – 2 theta = theta
• Or theta = 72 / 3
• Or theta = 24 degree C
• Now the temperature difference across A will be 36 – 24 = 12 degree C

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https://brainly.in/question/16004934

Answer 2

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