Question

Two rods A, B of same material have same length and same thickness. A has circular cross section and B has square cross section. Ratio of rates of flow through them under same temperature difference is,​

Answer 1

Explanation:

We know that for semi-circular rod amount of heat generated is given as:

Q

1 = πRKA(T 1 −T 2 )t

For straight rod amount of heat generated is given as:Q 2 = 2RKA(T 1 −T 2 )t

So taking there ratio, we find QQ2Q 1 = π/2

Answer 2

Answer:

We know that for semi-circular rod amount of heat generated is given as:

Q

1

=

πR

KA(T

1

−T

2

)t

For straight rod amount of heat generated is given as:

Q

2

=

2R

KA(T

1

−T

2

)t

So taking there ratio, we find

Q

2

Q1 =

π

2