two rods of same length and diameter are drawn from equal masses and same quantity of heat is supplied to the rods,find the ratio of expansions if the specific heat of the materials are of the ratio 2:3 and coefficient of linear expansion are in ratio 1:2
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Answer:
3/4
Explanation:
Heat given ΔH=msΔθ
ΔH∝sΔθ
We get s1Δθ1 = s2Δθ2
Also, change in length Δl = lαΔθ
And Δl1 / Δl2 = a1Δθ1 / a2Δθ2 =
a1 / a2 * s2 / s1
1/2 * 3/2
=3/4
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