Two rods one of aluminum of length 11 having coefficient of linear expansiona,, and other steel of length 12 having coefficient of linear expansion a, are joined end to end. The expansion in both the rods is same on variation of temperature. Then the value of is 11+12 11
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Answer:
length is inversely proportional to coefficient of linear expansion, thus
l
1
l
2
=
α
S
α
A
or 1+
l
1
l
2
=1+
α
S
α
A
or
l
1
l
1
+l
2
=
α
S
α
A
+α
S
or
l
1
+l
2
l
1
=
α
A
+α
S
α
S
Explanation:
hope it's helpful ✌
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