Math, asked by sweety3744, 1 year ago

two rooms having same perimeter. one is a square of side 15m and another is a rectangle of length 20 m. which room has a greater area and how much

Answers

Answered by Anonymous
11
\large\sf{\underline{\underline{ \ Square \ : \ }}}

Side = 15 cm

Perimeter = 4 × Side = 4 × 15 = 60 cm

\large\sf{\underline{\underline{ \ Rectangle \ : \ }}}

Length = 20 m

Breadth = ? m

Perimeter = 2 ( Length + Breadth )

= 2 ( 20 + ? )

Now,

It is given that both the perimeters are equal.

•°•

60 = 2 ( 20 + ? )

30 = 20 + ?

? = 10

Hence,

Breadth of Rectangle = 10 m

Now,

Area of the square = ( Side )² = ( 15 )² = 225 m²

Area of the rectangle = Length × Breadth

= 20 × 10 = 200 m²

From the calculated data, we can conclude that \sf{\underline{Square}} has a greater area.
Answered by khanshahid01497
0

Answer:

Square

side =15cm

Perimeter =4×side=60cm

Rectangle

Length=20m

Breath=x

Perimeter=(Length × Breath)

= 2. (20 × x)

**

60. =2(20× x)

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