Question

Two ropes 12 m and 16 m long are to be cut into small pieces of equal length. What will be the minimum length of each piece?

Answer 1

Answer:

4 metres

Step-by-step explanation:

In order to find the the minimum length of each piece, we need to obtain the HCF of 12 and 16.

Therefore,

$12 = 2 \times 2 \times 3 \\ \\ 16 = 2 \times 2 \times 2 \times 2$

Common factors of 12 and 16 are 2, 2

Therefore

HCF of 12 and 16 = 2 x 2 = 4

Thus, the minimum length of each piece will be 4 metres.

Answer 2

Answer:

4 m

Step-by-step explanation:

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