two ropes 12m and 18 m long are to be cut into small pieces of the same length .What will be the maximum length of each piece
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Answer:
12=2×2×3
18=2×3×3
Maximum length of the piece that has to be cut=H.C.F of 12m and 18m
Now HCF of 12 and 18 is 6
∴ Required length=6m
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