Question

Two ropes 16m and 20m long are to be cut into small pieces of equal length . What wil bw the maximum length of each piece

Answer 1

Answer:

Step-by-step explanation:

Equal length (given condition)

Given rope lengths have a multiple of 2 and 4

2*2*2*2=16m

2*2*5=20m

4*4=16m

4*5=20m

Given that maximum length thus 4m is our answer.

Answer 2

Maximum length of each piece = HCF of 16 & 20

16 = 2 *2 *2 *2

20 = 2* 2* 5

So, HCF = 2² = 4

So, length of each piece = 4 m

& we will have 9 such pieces