Question

two ropes 21 m and 36 m long are to be cut into small pieces of equal length. what will the maximum length of each pieces?​

Answer 1

Answer:

15 cm

Step-by-step explanation:

Answer 2

Answer:

3m

Step-by-step explanation:

in this question we need to find the HCF ( highest common factor)

so factors of 21 and 36 will be

21= 3 x 7

36 = 3 x 3 x 4

here the HCF is 3

so maximum length of each piece will be 3

and there will be a total of 7 pieces from first rope and 12 pieces from second rope.