Question

Two
ropes
are 64 cm and 80cm long-
What maximum pieces can be cut off equally
from the given ropes​

Answer 1

Answer:

64+80

144

16 multiply by 9 -144

the answer is 9

may be it help you

Answer 2

Step-by-step explanation:

First find the HCF of 64 and 80 to find the maximum length of the pieces.

Factors of 64 are 2x2x2x2x2x2

Factors of 80 are 2x2x2x2x5

So HCF will be 2x2x2x2 = 16cm.

So the length of each piece will be 16cm.

Please mark my answer as Brainliest answer..