two ropes of length 28 m and 36 m are to be cut into bits pf same length what is the greatest possible length of each bit
Answers
Answered by
32
Hi ,
Lengths of the two ropes are 28m
and 36m.
We have to find HCF of 28 and 36
28 = 2 × 2 × 7
36 = 2 × 2 × 3 × 3
HCF ( 28 , 36 ) = 2 × 2 = 4
Now greatest possible length of
each bit = 4 m
I hope this helps you.
:)
Lengths of the two ropes are 28m
and 36m.
We have to find HCF of 28 and 36
28 = 2 × 2 × 7
36 = 2 × 2 × 3 × 3
HCF ( 28 , 36 ) = 2 × 2 = 4
Now greatest possible length of
each bit = 4 m
I hope this helps you.
:)
Answered by
2
Answer:
4 m
Step-by-step explanation:
the maximum length of both rope are 4 m
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