Question

two ropes of length 28 m and 36 m are to be cut into bits pf same length what is the greatest possible length of each bit

Answer 1

Hi ,

Lengths of the two ropes are 28m

and 36m.

We have to find HCF of 28 and 36

28 = 2 × 2 × 7

36 = 2 × 2 × 3 × 3

HCF ( 28 , 36 ) = 2 × 2 = 4

Now greatest possible length of

each bit = 4 m

I hope this helps you.

:)

Answer 2

Answer:

4 m

Step-by-step explanation:

the maximum length of both rope are 4 m