two ropes of length 28m and 36m are to be cut into bits of same length. find the greatest possible length for each bit.
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two ropes of length 28m and 36m are to be cut into bits of same length. find the greatest possible length for each bit.
Hi ,
your answer is
Lengths of the two ropes are 28m
and 36m.
We have to find HCF of 28 and 36
28 = 2 × 2 × 7
36 = 2 × 2 × 3 × 3
HCF ( 28 , 36 ) = 2 × 2 = 4
Now greatest possible length of
each bit = 4 m
I hope this helps you.
:)
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