Math, asked by sharmaanand450, 10 months ago

two ropes of length 28m and 36m are to be cut into bits of same length. find the greatest possible length for each bit.​

Answers

Answered by mohapatramadhusmita
4

Step-by-step explanation:

two ropes of length 28m and 36m are to be cut into bits of same length. find the greatest possible length for each bit.

Hi ,

your answer is

Lengths of the two ropes are 28m

and 36m.

We have to find HCF of 28 and 36

28 = 2 × 2 × 7

36 = 2 × 2 × 3 × 3

HCF ( 28 , 36 ) = 2 × 2 = 4

Now greatest possible length of

each bit = 4 m

I hope this helps you.

:)

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